Envers return QueryException on AuditReaderFactory query composite property - hibernate-envers

Envers cannot find composite property in Embedded class Audited. I have :
#Embeddable
public class Allocation {
private Long value;
...
}
#Entity
#Table(name = "payment")
#Audited
#AuditTable(value="payment_allocation")
public class PaymentEntity extends AbstractEntity {
// All propert is not Audited except Allocation
#Embedded
#NotAudited
private Transaction transaction;
#Audited
#Embedded
private Allocation allocation;
...
}
So when I call :
AuditReaderFactory
.get(entityManager)
.createQuery()
.forRevisionsOfEntity(PaymentEntity.class, true, true)
.add(AuditEntity.property("allocation.value").eq(1l))
.getResultList();
I have a
org.hibernate.QueryException: could not resolve property: allocation of: ....PaymentEntity_AUD
I try just "value" and I had same exception.
I want history of all Payments where value was 1L. So, There are something different to access a composite property like when we build a Query?

So, I found solution on : https://hibernate.atlassian.net/browse/HHH-9178
the name of property not "allocation.value" but "allocation_value".

Related

how to filter out entity object inside entity in rest api

I am using Spring Boot to implement rest api. There are three entities SeqTb, PairTb, and GroupTb and they are nested. SeqTb has manytoone with PairTb. PairTb has onetomany relationship with SeqTb and also manytoone with GroupTb.
//SeqTb.java
#Entity
#Table(name="SEQ_TB")
public class SeqTb implements Serializable {
.......
#ManyToOne
#JoinColumn(name="PAIR_ID")
private PairTb pairTb;
......
}
// PairTb.java
#Entity
#Table(name="PAIR_TB")
#NamedQuery(name="PairTb.findAll", query="SELECT p FROM PairTb p")
public class PairTb implements Serializable {
#ManyToOne
#JoinColumn(name="GROUP_ID")
private GroupTb groupTb;
#OneToMany(mappedBy="pairTb", cascade=CascadeType.ALL)
private List<SeqTb> seqTbs;
}
//GroupId.java
#Entity
#Table(name="GROUP_TB")
public class GroupTb implements Serializable {
//bi-directional many-to-one association to PairTb
#OneToMany(mappedBy="groupTb", cascade=CascadeType.ALL)
private List<PairTb> pairTbs;
}
In my controller GET request with analysisId was handled in the following way:
#RequestMapping(
value = "/api/seqs/{analysis_id}",
method = RequestMethod.GET,
produces = MediaType.APPLICATION_JSON_VALUE)
public ResponseEntity<SeqTb> getSeqByAnalysisId(#PathVariable("analysis_id") String analysis_id) {
SeqTb seq = seqService.findByAnalysisId(analysis_id);
return new ResponseEntity(seq, HttpStatus.OK);
}
I also create a bean class SeqServiceBean that extends the interface SeqService which in turn calls methods from the following JPA repository for query.
//SeqRepository.java
#Repository
public interface SeqRepository extends JpaRepository<SeqTb, Integer> {
#Override
public List<SeqTb> findAll();
public List<SeqTb> findByAnalysisId(String analysisId);
}
When I query a SeqTb object with SeqTb.PairTb == null, the api works just fine. However, if the analysisId I put in the url belongs to a SeqTb record that associates with a pairId which in turn belongs to a groupId, the program would go nuts. Below is the output, the first part output is correct (bold text). After that it keeps printing PairTb and GroupTb in loops (repeating keywords pairTb, groupTb).
{"rowId":8,"analysisId":"cce8d2c2-a6dc-4ee9-ba97-768f058abb50","analyteCode":"D","center":"UCSC",
"pairTb":{"rowId":4,"pairCode":"01ad975d-c2ed-4e4d-bd3b-c9512fc9073c","groupTb":{"rowId":1,"groupName":"PAWG_pilot-50","pairTbs":[{"rowId":1,"pairCode":"00ad0ffe-2105-4829-a495-1c2aceb5bb31","groupTb":{"rowId":1,"groupName":"PAWG_pilot-50","pairTbs":
Meanwhile I got lots of errors from tomcat server:
Caused by: java.lang.IllegalStateException: getOutputStream() has already been called for this response
at org.apache.catalina.connector.Response.getWriter(Response.java:565) ~[tomcat-embed-core-8.0.32.jar:8.0.32]
at org.apache.catalina.connector.ResponseFacade.getWriter(ResponseFacade.java:212) ~[tomcat-embed-core-8.0.32.jar:8.0.32]
How do I ignore the nested entity object inside an entity and get only the meaning columns?
You can also annotate a property with #JsonIgnore in order to not output that field.
Found the solution. Created a value object that only contains the specific columns from entity and leave out the nested entity object. And it works.

java.lang.IllegalArgumentException: You have provided an instance of an incorrect PK class for this find operation.

I'm trying to create a URI and returns an object looking for NIF. (One custom filter)
I have tried to replicate the search by id but does not work, the truth, I'm not sure what I do. I have two classes with these functions
ClientesAbstractFacade.java
public T findNif(Object nif) {
return getEntityManager().find(entityClass, nif);
}
lientesFacadeREST.java
#GET
#Path("nif/{nif}")
#Produces({MediaType.APPLICATION_JSON})
public Clientes findNif(#PathParam("nif") String nif) {
return super.findNif(nif);
}
And here POJO
#Entity
#Table(name = "clientes")
public class Clientes implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Basic(optional = false)
#Column(name = "id")
private Integer id;
As you can see, I'm trying to do custom searches, something easy, and then implement a login.
But I can not even filter by nif, these return error 500
java.lang.IllegalArgumentException: You have provided an instance of an incorrect PK class for this find operation. Class expected : class java.lang.Integer, Class received : class java.lang.String.
The exception says it all:
IllegalArgumentException: You have provided an instance of an incorrect PK class for this find operation. Class expected : class java.lang.Integer, Class received : class java.lang.String
The getEntityManager().find(entityClass, nif) is working on the Primary Key column of your Table. This is, as the exception states, an Integer.
I guess you want to use your NamedQueries and have thus to use createNamedQuery-methods of the EntityManager.
So your find-method should look something like that:
public T findNif(String nif) {
return (T) getEntityManager().createNamedQuery("Clientes.findByNif", Clientes.class)
.setParameter("nif", nif).getSingleResult();
}

Mapping abstract classes with includePaths

I have a question regarding mapping of Hibernate Search and using an abstract base class.
I'm getting the following error
Caused by: org.hibernate.search.SearchException: Found invalid #IndexedEmbedded->paths configured on class nl.project.model.social.AbstractGroup, member language: language.id
at org.hibernate.search.engine.spi.AbstractDocumentBuilder.validateAllPathsEncountered(AbstractDocumentBuilder.java:901)
at org.hibernate.search.engine.spi.AbstractDocumentBuilder.checkForIndexedEmbedded(AbstractDocumentBuilder.java:880)
at org.hibernate.search.engine.spi.AbstractDocumentBuilder.initializeMemberLevelAnnotations(AbstractDocumentBuilder.java:489)
at org.hibernate.search.engine.spi.AbstractDocumentBuilder.initializeClass(AbstractDocumentBuilder.java:391)
at org.hibernate.search.engine.spi.AbstractDocumentBuilder.<init>(AbstractDocumentBuilder.java:174)
at org.hibernate.search.engine.spi.DocumentBuilderContainedEntity.<init>(DocumentBuilderContainedEntity.java:60)
at org.hibernate.search.spi.SearchFactoryBuilder.initDocumentBuilders(SearchFactoryBuilder.java:396)
at org.hibernate.search.spi.SearchFactoryBuilder.buildNewSearchFactory(SearchFactoryBuilder.java:222)
at org.hibernate.search.spi.SearchFactoryBuilder.buildSearchFactory(SearchFactoryBuilder.java:146)
at org.hibernate.search.event.impl.FullTextIndexEventListener.initialize(FullTextIndexEventListener.java:130)
at org.hibernate.search.hcore.impl.HibernateSearchIntegrator.integrate(HibernateSearchIntegrator.java:83)
at org.hibernate.internal.SessionFactoryImpl.<init>(SessionFactoryImpl.java:301)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1750)
Based on the following mapping configuration
#Entity
#Table
#Inheritance(strategy = InheritanceType.SINGLE_TABLE)
#DiscriminatorColumn(name = "DTYPE", discriminatorType= DiscriminatorType.STRING, length = 3)
#Indexed
public abstract class AbstractGroup implements Serializable, IEntity, IPhoto{
protected Language language;
#ManyToOne(fetch=FetchType.LAZY, cascade=CascadeType.ALL)
#JoinColumn(name="FK_LanguageId")
#Cache(usage=CacheConcurrencyStrategy.NONSTRICT_READ_WRITE,region=CacheRegion.NEVERCHANGE)
#NotNull
#IndexedEmbedded(includePaths={"id"})
public Language getLanguage() {
return language;
}
}
#Entity
#DiscriminatorValue(value = "GRP")
#Cache(usage=CacheConcurrencyStrategy.NONSTRICT_READ_WRITE,region=CacheRegion.GROUP)
public class Group extends AbstractGroup{
#Entity
#DiscriminatorValue(value = "PGE")
#Cache(usage=CacheConcurrencyStrategy.NONSTRICT_READ_WRITE,region=CacheRegion.GROUP)
public class Page extends AbstractGroup{
I've tried putting #Indexed on the subclass but this gives the same error.
The #Indexed annotation should indeed be on the sub classes. However, I am not sure what this should have to to with te discriminator column. JPA and Search annotations should be orthogonal. Two different things really. Btw, how does your Language entity look like? See also https://forum.hibernate.org/viewtopic.php?f=9&t=993097&hilit=abstract+base+class

JPA/Hibernate OneToMany & ManyToOne annotations

I'm writing code that looks like Google Latitude (locate a user).
I'm under tomcat 6.0.33, using jpa/hibernate, and easybeans 1.1
They work independently, but when I try to link them it fails:
Caused by: javax.persistence.PersistenceException: [PersistenceUnit: entity] Unable to build EntityManagerFactory
Caused by: org.hibernate.HibernateException: Unable to instantiate default tuplizer [org.hibernate.tuple.entity.PojoEntityTuplizer]
Here is the code:
public class Personne{
#ManyToOne(fetch=FetchType.EAGER, cascade={ CascadeType.PERSIST,CascadeType.MERGE })
public Personne getOwner() {
return owner;
}
}
public class MaPosition{
#OneToMany
public List<Personne> getFriends() {
return friends;
}
}
Thanks for your help ;)
does it work if you add a mappedBy to your OneToMany?
public class MaPosition{
#OneToMany(mappedBy="owner")
public List<Personne> getFriends() {
return friends;
}
}
JPA/Hibernate OneToMany & ManyToOne annotations for class person and person address.
So one person can have many addresses..... and I used this It worked...
One to many....
public class Person{
#OneToMany(mappedBy="person", targetEntity=Address.class, cascade=CascadeType.MERGE)
private Set<Address> addressList = HashSet<Address>();
//Getters and Setters.....
}
Many to one....
public class Address{
#ManyToOne
#JoinColumn(name="PERSON_ID")
private Person person;
//Getters and Setters.....
}

How do I represent this using JPA?

I would like a 'RolesPlayed' entity with the following columns
user
role
department/project/group
All the three columns above constitute a composite primary key. I would like to know if defining a column to be one of department/project/group possible ? If yes, how ? Or do I need to break the entity into DepartmentRoles, GroupRoles and ProjectRoles.
Thanks.
You could use polymorphism with an abstract base class to do that.
#Entity
public class RolePlayed {
#ManyToOne
private User user;
#ManyToOne
private Role role;
#ManyToOne
private Body body;
...
}
#Entity
#Inheritance(strategy = InheritanceType.JOINED)
public abstract class Body {
...
}
#Entity
public class Department extends Body {
...
}
#Entity
public class Project extends Body {
...
}
#Entity
public class Group extends Body {
...
}
Check out the Polymorphism section in the Java Enterprise tutorial for a good overview.
Alternatively, you could also make the RolePlayed entity abstract, with DepartmentRole, GroupRole and ProjectRole implementations.