sed to replace all line on the first match not working - sed

Question

Here's the file that i want to be edited
server {
listen 99;
listen 200;
listen 300;
server_name xxxx;
root xxxx;
...
I want to change the first line containing 'listen' to new words like ' listen_xyz 40;', here's my code:
sed -i -e '0,/listen/s/.*/listen_xyz 40;/' file
why it also replace first line (not matching with the pattern), so my file now look like this:
listen_xyz 40;
listen_xyz 40;
listen 200;
listen 300;
server_name xxxx;
root xxxx;
...
whats wrong with my sed code, why it replace the first line even tho its not matchg my pattern?

Answer 1

Try:
$ sed -e '0,/listen/ s/listen.*/listen_xyz 40;/' file
server {
listen_xyz 40;
listen 200;
listen 300;
server_name xxxx;
root xxxx;
...
Explanation
0,/listen/ is a range. It matches all lines from the beginning of the file to the first line that matches the regex listen. Thus, this matches the first two lines of your sample file.
s/.*/listen_xyz 40;/ is a substitute command. It is executed for any line in the range. It replaces any line (.*) with listen_xyz 40;. This means that it replace server { as well as listen 99;.
By changing the substitute command to s/listen.*/listen_xyz 40;/, we make sure that it only replaces lines that contain listen.