There are three columns id : integer auto increment , col_jsonb: jsonb , date: timestamp.
I want to merge col_jsonb row values into json build object based on date,
the required output
Table:
+----+----------------+------------+
| id | col_jsonb | date |
+----+----------------+------------+
| 1 | {"Morning":10} | 2020-08-09 |
| 2 | {"Evening":20} | 2020-08-09 |
| 3 | {"Night":30} | 2020-08-09 |
| 4 | {"Morning":20} | 2020-08-10 |
+----+----------------+------------+
Expected o/p:
+----+----------------------------------------------+------------+
| id | col_jsonb | date |
+----+----------------------------------------------+------------+
| 1 | [{"Morning":10},{"Evening":20},{"Night":30}] | 2020-08-09 |
| 2 | {"Morning":20} | 2020-08-10 |
+----+----------------------------------------------+------------+
Try This query:
select
row_number() over (order by date_) as "id",
jsonb_agg(col_jsonb),
date_ as "Date"
from
example
group by
date_
row_number is added for numbering of rows if required
DEMO
Related
I have an "Orders" table:
+---------+-------------+
| OrderID | InvoiceDate |
+---------+-------------+
| 1 | 15/02/2022 |
| 123 | 20/01/2022 |
+---------+-------------+
and a "Rows" table:
+---------+-------+--------+
| OrderID | RowID | Value |
+---------+-------+--------+
| 1 | 1 | 100,00 |
| 1 | 2 | 200,00 |
| 1 | 3 | 50,00 |
| 123 | 1 | 10,00 |
| 123 | 2 | 20,00 |
+---------+-------+--------+
As shown in the example, it may happen that an order with a higher OrderID value has a lower InvoiceDate value.
In my report I would like to show each order, along with the sum of each row's value, ordered by date:
+-------------+---------+--------+
| InvoiceDate | OrderID | Value |
+-------------+---------+--------+
| 20/01/2022 | 123 | 30,00 |
| 15/02/2022 | 1 | 350,00 |
+-------------+---------+--------+
My problem is that in order to create an OrderValue formula field with Sum({Rows.Value}, {Orders.OrderID}), I first need to group by Rows.OrderID
But this way rows are sorted by OrderID, and I don't know how to sort them by date.
Add a group total of Maximum (or minimum, or Average) Order Date by Order ID.
Go to the menu option of Report, Group Sort Expert...
and sort the groups by that total.
I calculate my metrics with SQL and publish the resulting table to Tableau Server. Afterward, use this data source to create charts and dashboards.
For one analysis, I already calculated the measures per day with SQL. When I use the resulting table in Tableau, it aggregates these measures to SUM by default. However, I don't want to have SUM or AVG of the average or SUM of the Percentiles.
What I want is the result when I don't select date dimension and not GROUP BY date in SQL as attached below.
Here is the query:
SELECT
-- date,
COUNT(DISTINCT id) AS count_of_id,
AVG(timediff_in_sec) AS avg_timediff,
PERCENTILE_CONT(0.25) WITHIN GROUP(ORDER BY timediff_in_sec) AS percentile_25,
PERCENTILE_CONT(0.50) WITHIN GROUP(ORDER BY timediff_in_sec) AS percentile_50
FROM
(
--subquery
) AS t1
-- GROUP BY date
Here are the first 10 rows of the resulting table:
+------------+--------------+-------------+---------------+---------------+
| date | avg_timediff | count_of_id | percentile_25 | percentile_50 |
+------------+--------------+-------------+---------------+---------------+
| 10/06/2020 | 61,65186364 | 22 | 8,5765 | 13,3015 |
| 11/06/2020 | 127,2913333 | 3 | 15,6045 | 17,494 |
| 12/06/2020 | 306,0348214 | 28 | 12,2565 | 17,629 |
| 13/06/2020 | 13,2664 | 5 | 11,944 | 13,862 |
| 14/06/2020 | 16,728 | 7 | 14,021 | 17,187 |
| 15/06/2020 | 398,6424595 | 37 | 11,893 | 19,271 |
| 16/06/2020 | 293,6925152 | 33 | 12,527 | 17,134 |
| 17/06/2020 | 155,6554286 | 21 | 13,452 | 16,715 |
| 18/06/2020 | 383,8101429 | 7 | 266,048 | 493,722 |
+------------+--------------+-------------+---------------+---------------+
How can I achieve the desired output above?
Drag them all into the dimensions list, then they will be static dimensions. For your use you could also just drag the Date field to Rows. Aggregating 1 value, which you have for each date, returns the same value whatever the aggregation type.
Take the following data and queries:
create table if not exists my_example(a_group varchar(1)
,the_date date
,metric numeric(4,3)
);
INSERT INTO my_example
VALUES ('1','2018-12-14',0.514)
,('1','2018-12-15',0.532)
,('2','2018-12-15',0.252)
,('3','2018-12-14',0.562)
,('3','2018-12-15',0.361);
select
t1.the_date
,t1.a_group
,t1.metric AS current_metric
,lag(t1.metric, 1) OVER (ORDER BY t1.a_group, t1.the_date) AS previous_metric
from
my_example t1;
Which yields the following results:
+------------+---------+----------------+-----------------+
| the_date | a_group | current_metric | previous_metric |
+------------+---------+----------------+-----------------+
| 2018-12-14 | 1 | 0.514 | NULL |
| 2018-12-15 | 1 | 0.532 | 0.514 |
| 2018-12-15 | 2 | 0.252 | 0.532 |
| 2018-12-14 | 3 | 0.562 | 0.252 |
| 2018-12-15 | 3 | 0.361 | 0.562 |
+------------+---------+----------------+-----------------+
I expected the value of previous_metric for the lone a_group==2 row to be NULL. However, as you can see, the value is showing as 0.532, which is being picked up from the previous row. How can I modify this query to yield a value of NULL as I expected?
You need to use LAG with a partition on a_group, since you want the lag values from a specific frame:
SELECT
t1.the_date,
t1.a_group,
t1.metric AS current_metric,
LAG(t1.metric, 1) OVER (PARTITION BY t1.a_group ORDER BY t1.the_date)
AS previous_metric
FROM my_example t1;
I had to create a cross tab table from a Query where dates will be changed into column names. These order dates can be increase or decrease as per the dates passed in the query. The order date is in Unix format which is changed into normal format.
Query is following:
Select cd.cust_id
, od.order_id
, od.order_size
, (TIMESTAMP 'epoch' + od.order_date * INTERVAL '1 second')::Date As order_date
From consumer_details cd,
consumer_order od,
Where cd.cust_id = od.cust_id
And od.order_date Between 1469212200 And 1469212600
Order By od.order_id, od.order_date
Table as follows:
cust_id | order_id | order_size | order_date
-----------|----------------|---------------|--------------
210721008 | 0437756 | 4323 | 2016-07-22
210721008 | 0437756 | 4586 | 2016-09-24
210721019 | 10749881 | 0 | 2016-07-28
210721019 | 10749881 | 0 | 2016-07-28
210721033 | 13639 | 2286145 | 2016-09-06
210721033 | 13639 | 2300040 | 2016-10-03
Result will be:
cust_id | order_id | 2016-07-22 | 2016-09-24 | 2016-07-28 | 2016-09-06 | 2016-10-03
-----------|----------------|---------------|---------------|---------------|---------------|---------------
210721008 | 0437756 | 4323 | 4586 | | |
210721019 | 10749881 | | | 0 | |
210721033 | 13639 | | | | 2286145 | 2300040
I need help with a bit of a crazy single-query goal please that I'm not sure if GROUP BY or sub-SELECT applies to?
The following query:
SELECT id_finish, description, inside_rate, outside_material, id_part, id_metal
FROM parts_finishing AS pf
LEFT JOIN parts_finishing_descriptions AS fd ON (pf.id_description=fd.id);
Returns the results like the following:
+-------------+-------------+------------------+--------------------------------+
| description | inside_rate | outside_material | id_part - id_finish - id_metal |
+-------------+-------------+------------------+--------------------------------+
| Nickle | 0 | 33.44 | 4444-44-44, 5555-55-55 |
+-------------+-------------+------------------+--------------------------------+
| Bend | 11.22 | 0 | 1111-11-11 |
+-------------+-------------+------------------+--------------------------------+
| Pack | 22.33 | 0 | 2222-22-22, 3333-33-33 |
+-------------+-------------+------------------+--------------------------------+
| Zinc | 0 | 44.55 | 6000-66-66 |
+-------------+-------------+------------------+--------------------------------+
I need the results to return in the fashion below but there are catches:
I need to group by either the inside_rate column or the outside_material column but ORDER BY the description column but not ORDER BY or sort them by price (inside_rate and outside_material are the prices). So we know that they belong to a group if inside_rate is 0 or to the other group if outside_material is 0.
I need to ORDER BY the description column desc secondary after they are returned per group.
I need to return a list of parts (composed of three separate columns) for that inside/outside group / price for that finishing.
Stack format fix.
+-------------+-------------+------------------+--------------------------------+
| description | inside_rate | outside_material | id_part - id_finish - id_metal |
+-------------+-------------+------------------+--------------------------------+
| Bend | 11.22 | 0 | 1111-11-11 |
+-------------+-------------+------------------+--------------------------------+
| Pack | 22.33 | 0 | 2222-22-22, 3333-33-33 |
+-------------+-------------+------------------+--------------------------------+
| Nickle | 0 | 33.44 | 4444-44-44, 5555-55-55 |
+-------------+-------------+------------------+--------------------------------+
| Zinc | 0 | 44.55 | 6000-66-66 |
+-------------+-------------+------------------+--------------------------------+
The tables I'm working with and their data types:
Table "public.parts_finishing"
Column | Type | Modifiers
------------------+---------+-------------------------------------------------------------
id | bigint | not null default nextval('parts_finishing_id_seq'::regclass)
id_part | bigint |
id_finish | bigint |
id_metal | bigint |
id_description | bigint |
date | date |
inside_hours_k | numeric |
inside_rate | numeric |
outside_material | numeric |
sort | integer |
Indexes:
"parts_finishing_pkey" PRIMARY KEY, btree (id)
Table "public.parts_finishing_descriptions"
Column | Type | Modifiers
------------+---------+------------------------------------------------------------------
id not null | bigint | default nextval('parts_finishing_descriptions_id_seq'::regclass)
date | date |
description | text |
rate_hour | numeric |
type | text |
Indexes:
"parts_finishing_descriptions_pkey" PRIMARY KEY, btree (id)
The second table's first column is just id. (Why are we still dealing with a 1024 static width layout in 2015?)
I'd make an SQL fiddle though it refuses to load for me regardless of the browser.
Not entirely sure I understand your question. Might look like this:
SELECT pd.description, pf.inside_rate, pf.outside_material
, concat_ws(' - ', pf.id_part::text
, pf.id_finish::text
, pf.id_metal::text) AS id_part_finish_metal
FROM parts_finishing pf
LEFT JOIN parts_finishing_descriptions fd ON pf.id_description = fd.id
ORDER BY (pf.inside_rate = 0) -- 1. sorts group "inside_rate" first
, pd.description DESC NULLS LAST -- 2. possible NULL values last
;