How to open installed app with url_launcher else open in browser? - flutter

Question

like the title suggests, I use url_launcher to open some websites when the user taps a selected icon. The issue is that it opens the browser website if the associated app is not installed on the device otherwise nothing happens if said app is installed. The app just doesn't respond. From what I've read, its supposed to open the associated app anyway? Or am I mistaken?
Here's the onTap:
GestureDetector(
onTap: _launchTwitchURL,
child: Image.asset(
'assets/images/icon_twitch.png', // On click should redirect to an URL
width: 40.0,
height: 40.0,
),
),
And here's the call:
Future<void> _launchTwitchURL() async {
const url = 'https://www.twitch.tv/example';
if (await canLaunch(url)) {
await launch(url);
} else {
throw 'Could not launch $url';
}
}

Answer 1

Using android-intent package like #iDecode suggested to get it to work. appavailability might be a better suited/cleaner package depending on your needs.
Future<void> _launchTwitchURL() async {
const url = 'https://www.twitch.tv/example';
if (await canLaunch(url)) {
await launch(url);
} else if (Platform.isAndroid) {
final AndroidIntent intent = AndroidIntent(
action: 'action_view',
data: 'https://www.twitch.tv/example', // replace com.example.app with your applicationId
);
await intent.launch();
} else {
throw 'Could not launch $url';
}
}
Thanks #iDecode