I am working with google books in my flutter project.
im trying to create a method that that will call the diffrent books URL's that i have stored in a List and call the list back using a future builder.
The list look somthing like this:
List<String> toBeReadBooksList = ['https://www.googleapis.com/books/v1/volumes?q=1086782593+isbn'];
You can do it a way that similar to this:
final url = 'https://www.googleapis.com/books/v1/volumes?q=1086782593+isbn';
final response = await http.get(url)
if (response.statusCode == 200) {
// Here you need to parse data from response, you should replace it with your realization:
return Data.fromJson(jsonDecode(response.body));
} else {
throw Exception('Failed to load data from $url');
}
You can read more about how to work with requests and responses to/from the Network in Official Documentation.
Import url_launcher plugin import 'package:url_launcher/url_launcher.dart';
and in your pubspec.yaml dependecies url_launcher: ^5.7.10
add this and call it to open the selected url
_launchURL() async {
const url = toBeReadBooksList[0];//your list url
if (await canLaunch(url)) {
await launch(url);
}
else {
throw 'Could not launch $url';
}
}
I want to implement rate and share button in my app so I am using url_launcher and here I want to put url of my app.
Currently it is working as
url="https://play.google.com/store/apps/details?id=in.learncodeonline.lco";
but I want this type
url="https://play.google.com/store/apps/details?id={packageName}"
Just call this function with package Name
void shareAnyApp(String packageName) async {
var url = "https://play.google.com/store/apps/details?id=$packageName";
if (await canLaunch(url)) {
await launch(url);
}
}
To Get Current App Package use Package_info
PackageInfo packageInfo = await PackageInfo.fromPlatform();
shareAnyApp(packageInfo.packageName );
I have used the following method as specified in the documentation.
Future<void> launchUniversalLink(String url) async {
if (await canLaunch(url)) {
final bool nativeAppLaunchSuccess = await launch(url, forceSafariVC: false, universalLinksOnly: true);
print(nativeAppLaunchSuccess);
}else {
print('launch not successfull');
}
}
if I give URL = 'https://www.WhatsApp.com'
print(nativeAppLaunchSuccess); output ==> true
but still the app launches in the browser.
can anyone help me with this problem
Oh I'm sorry. This is my mistake.
Please use 'device_apps' flutter package and usage is below.
And here is a how to know app package name.
https://www.techmesto.com/find-android-app-package-name/
In ios, you know other app's custom Url schema that officially opened.
But usually we can not know that url.
So below ios code is executed, it will open appstore page and need to push 'open' button.
if (Platform.isAndroid) {
if (await DeviceApps.isAppInstalled('com.nbt.moves') ==
true) {
DeviceApps.openApp('com.nbt.moves');
}
} else {
const url =
'https://apps.apple.com/kr/app/%EC%BA%90%EC%8B%9C%EC%8A%AC%EB%9D%BC%EC%9D%B4%EB%93%9C-%EC%8A%A4%ED%85%9D%EC%97%85/id1400703652?uo=4';
if (await canLaunch(url)) {
await launch(url);
} else {
throw 'Could not launch $url';
}
}
I want Flutter App A to launch Flutter App B passing in arguments.
I want Flutter App B to read these arguments passed by Flutter App A.
How do I do this in Flutter on both iOS & Android?
if you know the package name you can do handle it this way
add this plugins to your pubspec
device_apps:
android_intent:
url_launcher:
openAnotherApp (data) async
{String dt = data['hello there'] as String;
bool isInstalled = await DeviceApps.isAppInstalled('com.another app');
if (isInstalled != false)
{
AndroidIntent intent = AndroidIntent(
action: 'action_view',
data: dt
);
await intent.launch();
}
else
{
String url = dt;
if (await canLaunch(url))
await launch(url);
else
throw 'Could not launch $url';
}
}
if you want to check app availability first use flutter_appavailability
If already installed then launch otherwise open link in WebView using url_launcher.
Hello I search a simple example (Android and iOS) to send SMS with this package
https://pub.dartlang.org/packages/url_launcher
In the plugin page I only see how to open sms native app with phone number, but no extra message
sms:<phone number>, e.g. sms:5550101234 Send an SMS message to <phone
number> using the default messaging app
On Android the full sms: URI is supported and you can send a message with a body like that (RFC5724):
_textMe() async {
// Android
const uri = 'sms:+39 348 060 888?body=hello%20there';
if (await canLaunch(uri)) {
await launch(uri);
} else {
// iOS
const uri = 'sms:0039-222-060-888?body=hello%20there';
if (await canLaunch(uri)) {
await launch(uri);
} else {
throw 'Could not launch $uri';
}
}
}
On iOS the official doc says you can only use the number field of The URI.
Instead as Konstantine pointed out, if you use a non standard URI and instead and instead of starting the query string with ? you use & it still works as well. It seems like an undocumented feature.
The sms scheme is used to launch the Messages app. The format for URLs
of this type is “sms:”, where is an optional parameter
that specifies the target phone number of the SMS message. This
parameter can contain the digits 0 through 9 and the plus (+), hyphen
(-), and period (.) characters. The URL string must not include any
message text or other information.
PS. to check the plaform you could use the dart.io library Platform class:
_textMe() async {
if (Platform.isAndroid) {
const uri = 'sms:+39 348 060 888?body=hello%20there';
await launch(uri);
} else if (Platform.isIOS) {
// iOS
const uri = 'sms:0039-222-060-888&body=hello%20there';
await launch(uri);
}
}
you can trying this for android and IOS:
sendMessage() async {
if(Platform.isAndroid){
//FOR Android
url ='sms:+6000000000?body=message';
await launch(url);
}
else if(Platform.isIOS){
//FOR IOS
url ='sms:+6000000000&body=message';
}
}
This answer is for the new people coming in here for answers.
The previous answers are right however they won't work on iOS.
The App might crash on iOS but work on Android.
so to solve that we need to implement sending SMS in the way given below
String? encodeQueryParameters(Map<String, String> params) {
return params.entries
.map((e) => '${Uri.encodeComponent(e.key)}=${Uri.encodeComponent(e.value)}')
.join('&');
}
Uri smsUri = Uri(
scheme: 'sms',
path: '$phoneNumber',
query: encodeQueryParameters(<String, String>{
'body':
'Hey this is message body'
}),
);
try {
if (await canLaunch(smsUri.toString())) {
await launch(smsUri.toString());
}
} catch (e) {
ScaffoldMessenger.of(context).showSnackBar(
const SnackBar(
content: Text('Some error occured'),
),
);
}
Final updated answer post flutter 3 and latest url launcher package
smsUri = Uri(scheme: 'sms', path: phoneNumber);
try {
print(smsUri.toString());
if (await canLaunchUrl(
smsUri,
)) {
await launchUrl(smsUri);
}
} catch (e) {
ScaffoldMessenger.of(context).showSnackBar(
const SnackBar(
content: const Text('Some error occured'),
),
);
}
Here is the updated answer for sending SMS based on the OS of the device. I have tried the previous answers but I was facing body text issues on IOS devices.
_launchSms() async {
try {
if (Platform.isAndroid) {
String uri = 'sms:$phoneNumber?body=${Uri.encodeComponent("Hello there")}';
await launchUrl(Uri.parse(uri));
} else if (Platform.isIOS) {
String uri = 'sms:$phoneNumber&body=${Uri.encodeComponent("Hello there")}';
await launchUrl(Uri.parse(uri));
}
} catch (e) {
ScaffoldMessenger.of(context).showSnackBar(
const SnackBar(
content: Text('Some error occurred. Please try again!'),
),
);
}
}