row[0] is a date formatted such that is shows as 8/16/22 in google sheets.
And for the code,
var date = Utilities.formatDate(new Date(row[0]), SpreadsheetApp.getActiveSpreadsheet().getSpreadsheetTimeZone(), "m/d/yy");
SpreadsheetApp.getUi().alert(date);
I expected the output of 8/16/22 but instead get the following:
My end goal is to have this date be pasted into a google doc template using the following line:
body.replaceText('{{date}}', date);
And here is the output of just SpreadsheetApp.getUi().alert(new Date(row[0]));
As written in official documentation:
m is minute, use M instead.
Related
Im trying to convert the first two columns of a cell into a Matlab time. First column {1,1} is the date in YYYY-MM-DD format and the second is the time in HH:MM format.
Any ideas where I'm going wrong? My code:
file = 'D:\Beach Erosion and Recovery\Bournemouth\Bournemouth Tidal
Data\tidal_data_jtide.txt'
fileID = fopen(file);
LT_celldata = textscan(fileID,'%D%D%D%D%d%[^\n\r]','delimiter',',');
formattime = 'yyyy-mm-dd HH:MM'
date = LT_celldata{1,1};
time = LT_celldata{1,2};
date_time = datenum('date','time'); code
Screenshot below is LT_celldata{1,1} :
You can combine variables date and time with the following code:
date = datetime(LT_celldata{1,1},'InputFormat','yyyy-MM-dd');
time = datetime(LT_celldata{1,2},'InputFormat','HH:mm:ss','Format','HH:mm:ss');
myDatetime = datetime(date + timeofday(time),'Format','yyyy-MM-dd HH:mm:ss');
The code uses timeofday function to combine date and time information from the two different variables. You may find more information and examples at this documentation page.
Hi I am a newbie and have a problem I have been trying to solve for weeks. I have a table imported from excel with dates in text format (because dates go back to 1700s) Most are in the format "mmmyyyy", so it is relatively easy to add "1" to the date, convert to date format, and sort in correct date order. The problem I have is that some of the dates in the table are simply "yyyy", and some are empty. I cannot find an expression that works to convert these last two to eg 1 Jan yyyy and 1 Jan 1000 within the same expression. Is this possible, or would I need to do this in two queries? Sorry if this question is very basic - I cannot find an answer anywhere.
TIA
You can do something like:
Public Function ConvertDate(Byval Expression As Variant) As Date
Dim Result As Date
If IsNull(Expression) Then
Result = DateSerial(1000, 1, 1)
ElseIf Len(Expression) = 4 Then
Result = DateSerial(Expression, 1, 1)
Else
Result = DateValue(Right(Expression, 4) & "/" & Left(Expression, 3) & "/1")
End If
ConvertDate = Result
End Function
I'm having trouble finding a good way of formatting a UTC-time stamp with this format: yyyyMMdd-HH:mm:ss.<three additional digits>
I wasn't able to find any character that represents milliseconds/hundredths, I'm not even sure this is possible, to parse that format that is.
Ideally I'd like to use the parseToStringDate that's part of the Date library.
My plan b is to convert yyyyMMdd-HH:mm:ss to milliseconds and then add the three last digits to that number.
Use yyyyMMdd-HH:mm:ss.SSS
This will get you milliseconds as well.
Test Code:
def now = new Date()
println now.format("yyyyMMdd-HH:mm:ss.SSS", TimeZone.getTimeZone('UTC'))
I would convert it like that:
def now = new Date()
println now.format("YYYYMMdd-HH:mm:ss")
You can try this:
TimeZone.getTimeZone('UTC')
Date date = new Date()
String newdate = date.format("YYYY-MM-dd HH:mm:ss.Ms")
log.info newdate
I have a Date string of following format:
'31-OCT-2013'
How do I convert this into Date of following format using Extjs 4:
'08/31/2013'
I am using IE8.
If you have string "31-OCT-2013", you need to:
Convert it into date object
var myDate = Ext.Date.parse("31-OCT-2013", 'd-M-Y');
Format it to as you want
Ext.Date.format(myDate, 'm/d/Y');
Try something like this:
If your day representation would be 2 digit with leading zero, then apply this
var date = Ext.Date.parse("31-OCT-2013", 'd-M-Y');
console.log(Ext.Date.format(date, 'm/d/Y'));
But if your day representation would be without a leading zero, then apply this
var date = Ext.Date.parse("31-OCT-2013", 'j-M-Y');
console.log(Ext.Date.format(date, 'm/d/Y'));
Check the docs for Ext.Date
I am very new to Selenium IDE or javascript and was using google to learn it and do some testing of my website application. In my application I need to input user name and date of activity as part of the testcase.
I used random string generator function I saw online and created a user-extension.js to be called in S-IDE for the user name and was using a storeEval command to generate a date 5 days from today's date to give in the date of activity field. But today being 26th of Apr, when I run the script it is generating a date of 31-Apr which is invalid date and the test is failing.
I again found some code snippets online on how to check if the date generated is valid and then pass valid date back. But when I append this to the user-extension.js (Selenium.prototype.doValidDay) that I am having, this function is not recognized by S-IDE more over my random string function is also not recognized. (Meaning I am not able to find the command when I type on the command line of S-IDE)
Can someone please help me understand how to append multiple commands in a userextension js? I even created 2 js and selected both of them in options tab. Still not working..
Please help...
Try This for getting future date.
Selenium.prototype.doTypeTodaysDate = function(locator){
var dates = new Date();
dates.setDate(dates.getDate() + 5);
var day = dates.getDate();
if (day < 10){
day = '0' + day;
}
month = dates.getMonth() + 1;
if (month < 10){
month = '0' + month;
}
var year = dates.getFullYear();
var prettyDay = day + '/' + month + '/' + year;
this.doType(locator, prettyDay);
}
Copy the above code into note pad and save as date.js
after that add the date.js file into selenium ide
Options->Selenium core Extensions->browse the file
Think it will work for you.
Thank you