Have a use case to get the row from Cassandra Table which has max size.
Is there any way to do it
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When we are loading a pyspark dataframe to a Hive table which contains few columns which are having the integer value greater than the Hive Int limit(Overflows the Hive Int value), it is observed that the value is getting rounded to the limit of Integer value and the rest of the cell value is getting abondeded. For that reason, it is decided to split the rows, which are having the overflown value, into multiple rows so that the total amount will not be lost.
can anyone please let me know how can we achieve this using pyspark
How to fetch the hive table partition min and max value in pyspark/beeline?
show partitions table shows all the partitions.
There is another post on same question but it uses a bash approach. Do we have any solution on pyspark?
I have a table partitioned by range in Postgres 10.6. Is there a way to tell one of its partitions to accept NULL for the column used as partition key?
The reason I need this is: my table size is 200GB and it's actually not yet partitioned. I want to partition it going forward, so I thought I would create an initial partition including all of the current rows, and then at the start of each month I would create another partition for that month's data.
The issue is, currently this table doesn't have the column I'll use for partitioning, so I want to add the column (initially null) and then tell that initial partition to hold all rows that have null in the partitioning key.
Another option would be to not add the column as null but to set an initial date value, but that would be time and space consuming because of the size of that table.
I would upgrade to v11 and initially define the partitioned table with just a default partition that contains all the NULL values.
Then you can add other partitions and gradually move the data by updating the NULL values.
I want to run the following command to create a column organized table:
CREATE TABLE T0 (ABC VARCHAR(8000)) IN abc_tablespace organize by column
I get the following error:
SQL0670N The statement failed because the row or column size of the resulting
table would have exceeded the row or column size limit: "3920". Table space
name: "ABC_TABLESPACE". Resulting row or column size: "8000". SQLSTATE=54010
I have the extended_row_sz enabled. I checked and verified this. Not sure if this is only valid for row org tables or not. I do not want to enable DB2_WORKLOAD=ANALYTICS. I have just set INTRA_PARALLEL YES. Anyone know how I can create this column in an column organized table?
You would need to create your table in a tablespace with a larger page size. Typically Column Organized tables are created in a 32K page-size tablespace, although this is not mandatory.
Setting DB2_WORKLOAD=ANALYTICS before creating a database https://www.ibm.com/support/knowledgecenter/SSEPGG_11.1.0/com.ibm.db2.luw.admin.dbobj.doc/doc/t0061527.html sets the default page size to 32K. As you don't want to enable this parameter, you will need to create a 32K (or 16K or 8K) tablespace (and bufferpool) and create your table in it.
Extended row size support does not apply to column-organized tables.
This is stated here: CREATE TABLE, if you search by the phrase above.
I want to partition an external table in hive based on range of numbers. Say numbers with 1 to 100 go to one partition. Is it possible to do this in hive?
I am assuming here that you have a table with some records from which you want to load data to an external table which is partitioned by some field say RANGEOFNUMS.
Now, suppose we have a table called testtable with columns name and value. The contents are like
India,1
India,2
India,3
India,3
India,4
India,10
India,11
India,12
India,13
India,14
Now, suppose we have a external table called testext with some columns along with a partition column say, RANGEOFNUMS.
Now you can do one thing,
insert into table testext partition(rangeofnums="your value")
select * from testtable where value>=1 and value<=5;
This way all records from the testtable having value 1 to 5 will come into one partition of the external table.
The scenario is my assumption only. Please comment if this is not the scenario you have.
Achyut